Optimal. Leaf size=132 \[ -a^{5/2} A \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )+\frac{5 a^3 B \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{16 \sqrt{b}}+\frac{1}{16} a^2 \sqrt{a+b x^2} (16 A+5 B x)+\frac{1}{24} a \left (a+b x^2\right )^{3/2} (8 A+5 B x)+\frac{1}{30} \left (a+b x^2\right )^{5/2} (6 A+5 B x) \]
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Rubi [A] time = 0.414349, antiderivative size = 132, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35 \[ -a^{5/2} A \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )+\frac{5 a^3 B \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{16 \sqrt{b}}+\frac{1}{16} a^2 \sqrt{a+b x^2} (16 A+5 B x)+\frac{1}{24} a \left (a+b x^2\right )^{3/2} (8 A+5 B x)+\frac{1}{30} \left (a+b x^2\right )^{5/2} (6 A+5 B x) \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(a + b*x^2)^(5/2))/x,x]
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Rubi in Sympy [A] time = 50.3528, size = 121, normalized size = 0.92 \[ - A a^{\frac{5}{2}} \operatorname{atanh}{\left (\frac{\sqrt{a + b x^{2}}}{\sqrt{a}} \right )} + \frac{5 B a^{3} \operatorname{atanh}{\left (\frac{\sqrt{b} x}{\sqrt{a + b x^{2}}} \right )}}{16 \sqrt{b}} + \frac{a^{2} \left (48 A + 15 B x\right ) \sqrt{a + b x^{2}}}{48} + \frac{a \left (24 A + 15 B x\right ) \left (a + b x^{2}\right )^{\frac{3}{2}}}{72} + \frac{\left (6 A + 5 B x\right ) \left (a + b x^{2}\right )^{\frac{5}{2}}}{30} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b*x**2+a)**(5/2)/x,x)
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Mathematica [A] time = 0.250968, size = 132, normalized size = 1. \[ -a^{5/2} A \log \left (\sqrt{a} \sqrt{a+b x^2}+a\right )+a^{5/2} A \log (x)+\frac{5 a^3 B \log \left (\sqrt{b} \sqrt{a+b x^2}+b x\right )}{16 \sqrt{b}}+\frac{1}{240} \sqrt{a+b x^2} \left (a^2 (368 A+165 B x)+2 a b x^2 (88 A+65 B x)+8 b^2 x^4 (6 A+5 B x)\right ) \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(a + b*x^2)^(5/2))/x,x]
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Maple [A] time = 0.009, size = 138, normalized size = 1.1 \[{\frac{Bx}{6} \left ( b{x}^{2}+a \right ) ^{{\frac{5}{2}}}}+{\frac{5\,Bxa}{24} \left ( b{x}^{2}+a \right ) ^{{\frac{3}{2}}}}+{\frac{5\,Bx{a}^{2}}{16}\sqrt{b{x}^{2}+a}}+{\frac{5\,B{a}^{3}}{16}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){\frac{1}{\sqrt{b}}}}+{\frac{A}{5} \left ( b{x}^{2}+a \right ) ^{{\frac{5}{2}}}}+{\frac{Aa}{3} \left ( b{x}^{2}+a \right ) ^{{\frac{3}{2}}}}-A{a}^{{\frac{5}{2}}}\ln \left ({\frac{1}{x} \left ( 2\,a+2\,\sqrt{a}\sqrt{b{x}^{2}+a} \right ) } \right ) +A\sqrt{b{x}^{2}+a}{a}^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b*x^2+a)^(5/2)/x,x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + a)^(5/2)*(B*x + A)/x,x, algorithm="maxima")
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Fricas [A] time = 0.282997, size = 1, normalized size = 0.01 \[ \left [\frac{75 \, B a^{3} \log \left (-2 \, \sqrt{b x^{2} + a} b x -{\left (2 \, b x^{2} + a\right )} \sqrt{b}\right ) + 240 \, A a^{\frac{5}{2}} \sqrt{b} \log \left (-\frac{b x^{2} - 2 \, \sqrt{b x^{2} + a} \sqrt{a} + 2 \, a}{x^{2}}\right ) + 2 \,{\left (40 \, B b^{2} x^{5} + 48 \, A b^{2} x^{4} + 130 \, B a b x^{3} + 176 \, A a b x^{2} + 165 \, B a^{2} x + 368 \, A a^{2}\right )} \sqrt{b x^{2} + a} \sqrt{b}}{480 \, \sqrt{b}}, \frac{75 \, B a^{3} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right ) + 120 \, A a^{\frac{5}{2}} \sqrt{-b} \log \left (-\frac{b x^{2} - 2 \, \sqrt{b x^{2} + a} \sqrt{a} + 2 \, a}{x^{2}}\right ) +{\left (40 \, B b^{2} x^{5} + 48 \, A b^{2} x^{4} + 130 \, B a b x^{3} + 176 \, A a b x^{2} + 165 \, B a^{2} x + 368 \, A a^{2}\right )} \sqrt{b x^{2} + a} \sqrt{-b}}{240 \, \sqrt{-b}}, -\frac{480 \, A \sqrt{-a} a^{2} \sqrt{b} \arctan \left (\frac{a}{\sqrt{b x^{2} + a} \sqrt{-a}}\right ) - 75 \, B a^{3} \log \left (-2 \, \sqrt{b x^{2} + a} b x -{\left (2 \, b x^{2} + a\right )} \sqrt{b}\right ) - 2 \,{\left (40 \, B b^{2} x^{5} + 48 \, A b^{2} x^{4} + 130 \, B a b x^{3} + 176 \, A a b x^{2} + 165 \, B a^{2} x + 368 \, A a^{2}\right )} \sqrt{b x^{2} + a} \sqrt{b}}{480 \, \sqrt{b}}, \frac{75 \, B a^{3} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right ) - 240 \, A \sqrt{-a} a^{2} \sqrt{-b} \arctan \left (\frac{a}{\sqrt{b x^{2} + a} \sqrt{-a}}\right ) +{\left (40 \, B b^{2} x^{5} + 48 \, A b^{2} x^{4} + 130 \, B a b x^{3} + 176 \, A a b x^{2} + 165 \, B a^{2} x + 368 \, A a^{2}\right )} \sqrt{b x^{2} + a} \sqrt{-b}}{240 \, \sqrt{-b}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + a)^(5/2)*(B*x + A)/x,x, algorithm="fricas")
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Sympy [A] time = 21.3915, size = 323, normalized size = 2.45 \[ - A a^{\frac{5}{2}} \operatorname{asinh}{\left (\frac{\sqrt{a}}{\sqrt{b} x} \right )} + \frac{A a^{3}}{\sqrt{b} x \sqrt{\frac{a}{b x^{2}} + 1}} + \frac{A a^{2} \sqrt{b} x}{\sqrt{\frac{a}{b x^{2}} + 1}} + 2 A a b \left (\begin{cases} \frac{\sqrt{a} x^{2}}{2} & \text{for}\: b = 0 \\\frac{\left (a + b x^{2}\right )^{\frac{3}{2}}}{3 b} & \text{otherwise} \end{cases}\right ) + A b^{2} \left (\begin{cases} - \frac{2 a^{2} \sqrt{a + b x^{2}}}{15 b^{2}} + \frac{a x^{2} \sqrt{a + b x^{2}}}{15 b} + \frac{x^{4} \sqrt{a + b x^{2}}}{5} & \text{for}\: b \neq 0 \\\frac{\sqrt{a} x^{4}}{4} & \text{otherwise} \end{cases}\right ) + \frac{B a^{\frac{5}{2}} x \sqrt{1 + \frac{b x^{2}}{a}}}{2} + \frac{3 B a^{\frac{5}{2}} x}{16 \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{35 B a^{\frac{3}{2}} b x^{3}}{48 \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{17 B \sqrt{a} b^{2} x^{5}}{24 \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{5 B a^{3} \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{16 \sqrt{b}} + \frac{B b^{3} x^{7}}{6 \sqrt{a} \sqrt{1 + \frac{b x^{2}}{a}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b*x**2+a)**(5/2)/x,x)
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GIAC/XCAS [A] time = 0.21954, size = 169, normalized size = 1.28 \[ \frac{2 \, A a^{3} \arctan \left (-\frac{\sqrt{b} x - \sqrt{b x^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a}} - \frac{5 \, B a^{3}{\rm ln}\left ({\left | -\sqrt{b} x + \sqrt{b x^{2} + a} \right |}\right )}{16 \, \sqrt{b}} + \frac{1}{240} \,{\left (368 \, A a^{2} +{\left (165 \, B a^{2} + 2 \,{\left (88 \, A a b +{\left (65 \, B a b + 4 \,{\left (5 \, B b^{2} x + 6 \, A b^{2}\right )} x\right )} x\right )} x\right )} x\right )} \sqrt{b x^{2} + a} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + a)^(5/2)*(B*x + A)/x,x, algorithm="giac")
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